Josse van Dobben de Bruyn

Leiden, Netherlands

Currently I'm a graduate student in mathematics at TU Delft. My hobbies include computer programming and making music. :-)

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Submultiplicative Hilbert space norm on $B(H)$

functional-analysis hilbert-spaces banach-spaces banach-algebras asked Mar 20 '16 at 16:03

math.stackexchange.com

8 votes

Open mapping theorem for complete non-metrizable spaces?

fa.functional-analysis topological-vector-spaces uniform-spaces asked May 21 '19 at 13:49

mathoverflow.net

7 votes

Do the operators in $B(E,F)$ separate points on the projective tensor product $F' \mathop{\tilde\otimes_\pi} E$?

fa.functional-analysis banach-spaces tensor-products asked Aug 28 '19 at 20:05

mathoverflow.net

7 votes

Metrizability of a topological vector space where every sequence can be made to converge to zero

fa.functional-analysis topological-vector-spaces locally-convex-spaces asked Mar 22 at 18:16

mathoverflow.net

5 votes

Does every non-Archimedean absolute value satisfy the ultrametric inequality?

abstract-algebra field-theory absolute-value valuation-theory asked Apr 19 '16 at 0:20

math.stackexchange.com

Top Answers

To prove Cayley-Hamilton theorem, why can't we substitute $A$ for $\lambda$ in $p(\lambda) = \det(\lambda I - A)$?

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How does the general spectral theorem generalize the simpler versions?

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All uses of LaTeX (I never use LaTeX except for …)

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Infinite connected graph

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Interchange finite and infinite sum

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Infinite product probability spaces

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amsthm with shared counters messes up autoref references

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A question about pure state

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A cycle of size at least $\frac{n}k$ in a graph with at least $3k$ vertices

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Is B(H) a Hilbert space?

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Every compact set $A \subset \mathbb{R}$ is bounded

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Does every non-Archimedean absolute value satisfy the ultrametric inequality?

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Do automorphisms of a finitely generated free module restrict to automorphisms on every invariant submodule?

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What TSP variant doesn't return to start point?

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Josse van Dobben de Bruyn

Submultiplicative Hilbert space norm on $B(H)$

Open mapping theorem for complete non-metrizable spaces?

Do the operators in $B(E,F)$ separate points on the projective tensor product $F' \mathop{\tilde\otimes_\pi} E$?

Metrizability of a topological vector space where every sequence can be made to converge to zero

Does every non-Archimedean absolute value satisfy the ultrametric inequality?