Eduardo

Brazil

2014
May
7
awarded Supporter
2013
Oct
27
awarded Teacher
Oct
26
answered Problem with permutations
Oct
16
comment If $n$ divides $2^{2^{n} +1}+1$ $\to$ $n$ divides $2^{n}+1$?
Thank you. That was all I wanted to know.
Oct
16
awarded Scholar
Oct
16
accepted If $n$ divides $2^{2^{n} +1}+1$ $\to$ $n$ divides $2^{n}+1$?
Oct
16
comment If $n$ divides $2^{2^{n} +1}+1$ $\to$ $n$ divides $2^{n}+1$?
Sorry, I made a mistake when typing the implication. I typed if $n$ divides $2^{2^{n} +1}+1$ $\to$ $n$ divides $2^{n}+n$ but the correct is if $n$ divides $2^{2^{n} +1}+1$ $\to$ $n$ divides $2^{n}+1$
Oct
16
revised If $n$ divides $2^{2^{n} +1}+1$ $\to$ $n$ divides $2^{n}+1$?
added 209 characters in body; edited title
Oct
16
awarded Student
Oct
16
comment Does $n \mid 2^{2^n+1}+1$ imply $n \mid 2^{2^{2^n+1}+1}+1$?
Sorry, I did not follow you. I posted a question on the topic math.stackexchange.com/questions/528908/…. Can you answer it? Thank you.
Oct
16
asked If $n$ divides $2^{2^{n} +1}+1$ $\to$ $n$ divides $2^{n}+1$?
Oct
16
comment Does $n \mid 2^{2^n+1}+1$ imply $n \mid 2^{2^{2^n+1}+1}+1$?
You are right. How did you figure out that for n = 57 the implication doesn't work backwards?
Oct
16
comment Does $n \mid 2^{2^n+1}+1$ imply $n \mid 2^{2^{2^n+1}+1}+1$?
I realize other thing. $f(n)$ is odd, so if $f(n) = n \cdot p$ then $n$ and $p$ is odd. So I think this comlete the proof.
Oct
16
awarded Editor
Oct
16
revised Does $n \mid 2^{2^n+1}+1$ imply $n \mid 2^{2^{2^n+1}+1}+1$?
added 2 characters in body
Oct
16
comment Does $n \mid 2^{2^n+1}+1$ imply $n \mid 2^{2^{2^n+1}+1}+1$?
I realize that $f(a \cdot b)$ is $(2^{a} + 1)(1 - 2^{a} + 2^{2a} - 2^{3a} + ... + (-1)^{b-1}2^{(b-1)a})$ only if b is odd. So, there is a problem on my proof.
Oct
16
answered Does $n \mid 2^{2^n+1}+1$ imply $n \mid 2^{2^{2^n+1}+1}+1$?