robjohn

West Hills, CA

none

Age: 55

the mean square The Mean Square
(with one standard deviation and several unusual ones)

aka Rob Johnson

$\LaTeX$ support for Chat

2h
comment Fate of (homework): The community voted.... now what?
What happens if a question with the homework tag is missed? Will the tag simply be removed from that question? What happens if the homework tag is the only tag on that question?
3h
awarded Nice Answer
4h
awarded Good Answer
9h
comment Inequality for absolute values
@Brad: You seem to have proven that $$|x+y|+|y+z|+|z+x|\le2(|x|+|y|+|z|)$$ but I don't see a proof of the question asked. The only place that $|x+y+z|$ appears on the right side of a $\le$ sign is in the "Now I will prove that" line.
11h
comment Paradox: increasing sequence that goes to $0$?
Why was this question, with more answers, marked as a duplicate of a far newer question?
12h
revised Reverse Cauchy Schwarz for integrals
include some things not included previously
20h
revised Reverse Cauchy Schwarz for integrals
mention the conditions on $p$ and $q$
21h
answered Reverse Cauchy Schwarz for integrals
22h
answered How to work out miles between Longitude values based on a Latitude value.
1d
comment Determining the number of valid TicTacToe board states in terms of board dimension
This should really be a comment to Rod's answer, but it is too long. A disclaimer to that fact at the outset would be good.
1d
comment Reverse Cauchy Schwarz for integrals
and avoids the scaling that I did.
1d
comment Reverse Cauchy Schwarz for integrals
Looking more closely, $(4)$ does not appear to be as identical to your inequality with $M$ and $m$ as I first thought. They play similar roles, but the proofs are a bit different to account for the distinction.
1d
comment Reverse Cauchy Schwarz for integrals
I kept this window open too long and didn't see your answer appear. Good answer. (+1) I think we both used the same idea; that is, I think $(4)$ in my answer is similar to your inequality with $M$ and $m$.
1d
answered Reverse Cauchy Schwarz for integrals
2d
awarded Yearling
2d
awarded Yearling
Jul
27
awarded Nice Answer
Jul
27
comment regression vs classification
This seems to simply reiterate answers from long ago. If you have something new to add, please clarify your answer.
Jul
27
comment Is there a way to calculate the area of this intersection of four disks without using an integral?
@qwr: Thanks. A diagram often makes an explanation clearer.
Jul
27
comment Is there a way to calculate the area of this intersection of four disks without using an integral?
I used Intaglio, which is only available for MacOS.
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