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Apr
20 |
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accepted | Laplace Transform of a Brownian motion |
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Apr
20 |
|
comment |
Laplace Transform of a Brownian motion Thanks for the answer. I was guessing that this might be so. Can you give a reference to the growth and continuity properties mentioned in your answer. For $\Omega$, I only wanted to know if the convergence is a.e. or not, your answer says this is so. |
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Apr
14 |
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awarded | Tumbleweed |
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Apr
7 |
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asked | Laplace Transform of a Brownian motion |
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Feb
6 |
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accepted | Product of complex numbers |
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Feb
6 |
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comment |
Product of complex numbers Thanks all: I only calculated that this will be true when $n=2$ and when the real parts nor the complex parts are zero (If my calculation is correct!). Did not think of the zero case! Micah's example demonstrated that this is indeed false for higher $n$ (atleast $n=3$). |
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Feb
6 |
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asked | Product of complex numbers |
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Jan
3 |
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comment |
Construction of i.i.d random variables Robert: Thanks for the nice answer. The construction is surprising for me but very nice. |
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Jan
3 |
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accepted | Construction of i.i.d random variables |
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Jan
2 |
|
asked | Construction of i.i.d random variables |
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Dec
21 |
|
comment |
Construction of an increasing function from a general function coffeemath: Thanks for the answer. The infimum definition was the one I was after. |
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Dec
21 |
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accepted | Construction of an increasing function from a general function |
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Dec
21 |
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comment |
Construction of an increasing function from a general function Stefan: Thanks for the nice observation (that recursion is not possible). $g(x) = \inf\limits_{y\geq x} f(y)$ works perfectly for me. |
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Dec
21 |
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asked | Construction of an increasing function from a general function |
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Nov
27 |
|
comment |
Bivariate polynomials over finite fields Qiaochu: Thanks for pointing me in the right direction. I have no idea of algebraic geometry but I think it will be very interesting. |
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Nov
27 |
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accepted | Bivariate polynomials over finite fields |
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Nov
27 |
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asked | Bivariate polynomials over finite fields |
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Sep
18 |
|
comment |
Local compactness of a subspace of a locally compact metric space Thanks. I understand it now. |
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Sep
18 |
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accepted | Local compactness of a subspace of a locally compact metric space |
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Sep
17 |
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comment |
Local compactness of a subspace of a locally compact metric space Thanks for your answer. From your reply, $O_n$ is a compact subset of $M_n$. Considering our new space as $O_n$ with the subspace topology, I wanted to know if it is locally compact. Precisely, I wanted to show that if $A \in O_n$ then there exists a compact set $K$ (in the subspace topology) such that $A \in K \subset O_n$. I am unable to see how your argument proves this. |
