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Apr
11 |
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awarded | Yearling |
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Apr
11 |
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awarded | Yearling |
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May
7 |
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awarded | Tumbleweed |
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Apr
30 |
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accepted | Constructing a Measure from a Function |
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Apr
30 |
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revised |
Image of Thom Class under Sequence of Maps? added 425 characters in body |
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Apr
30 |
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asked | Image of Thom Class under Sequence of Maps? |
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Dec
14 |
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accepted | Relationship between the $2$-plane bundles over $S^2$ and $\mathbb{Z}$ |
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Dec
1 |
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accepted | Periodic Solutions for a System |
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Nov
30 |
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comment |
Periodic Solutions for a System That certainly makes a lot more sense now. Is there a way from that new system to get our periodic solutions? I'm probably missing something easy here, but I'm a bit forgetful on how to solve it. |
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Nov
30 |
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revised |
Periodic Solutions for a System added 57 characters in body |
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Nov
30 |
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asked | Periodic Solutions for a System |
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Nov
15 |
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comment |
Constructing a Measure from a Function Thanks for the clear explanation! That made perfect sense. |
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Nov
15 |
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comment |
Constructing a Measure from a Function Other than using my "interval jumping argument", what's a clearer way to explain that $G_N(x)=\sum_{n=1}^N a_n1_{[c_n,\infty)}(x)$ is right-continuous? It seems that when I try to explain that this is right-continuous, it uses the same logic as showing that the desired function is right-continuous in the first place. I am a fan of that clever use of the indicator function though! |
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Nov
15 |
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comment |
Constructing a Measure from a Function Actually, it does seem this argument is still valid. I can just replace $c_{n+1}$ with the condition that it holds for every $c_i>c_n$. That is, the function remains constant for all $x$ where $c_n\leq x<c_i$ for all $c_i>c_n$. Then the constant interval would jump to another when $x$ reaches one of these $c_i$'s. |
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Nov
15 |
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revised |
Constructing a Measure from a Function added 46 characters in body |
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Nov
15 |
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comment |
Constructing a Measure from a Function Note that the function/summation remains constant for all $x$ where $c_n\leq x < c_{n+1}$. It then "jumps" to the next interval when $x=c_{n+1}$. That is, the function is basically just intervals jumping to the next, where each interval is closed on the left. (as in en.wikipedia.org/wiki/File:Right-continuous.svg) Actually, I'm not too sure if this argument works because I'm assuming that the $c_n$'s are non-decreasing. Could I somehow build an analogous argument by re-ordering the $c_n$'s or doing something similar? |
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Nov
15 |
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revised |
Constructing a Measure from a Function added 37 characters in body |
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Nov
15 |
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asked | Constructing a Measure from a Function |
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Nov
3 |
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comment |
How do I write this in set builder notation? Note that there are many infinitely many ways to express that set since you need only have a representation that contains those 6 elements (and assuming that it is a non-decreasing order, that it does not contain all other elements less than $35$). |
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Oct
28 |
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comment |
Looking for a simple problem for math demonstration One similar in the problem-solving method (deducing step-by-step) would be en.wikipedia.org/wiki/Pirate_game. It's not as similar as you might think, and it's quite fun. Who doesn't like pirates and gold? |
