rafaelm

Zagreb, Croatia

May
8
awarded Caucus
Mar
27
answered Right-adjoint functors are left-exact?
Mar
15
comment Image of Homomorphism of Lie groups
Thanks. For your last paragraph, I can show that Lie group homomorphism has constant rank, and that injective map with constant rank must be an immersion (these facts are propositions in Lee's book).
Mar
15
accepted Image of Homomorphism of Lie groups
Mar
14
comment Image of Homomorphism of Lie groups
If you would please post your comment as an answer, I would accept it!
Mar
14
comment Image of Homomorphism of Lie groups
Thank you, that is what I was looking for. At first, I thought that I must work the coordinate charts explicitely. I got the smoothness of multiplicaion myself. And for the kernel part, I can show that Lie group homomorphism must be of constant rank, and that means that level sets are embedded submanifolds of domain, and therefore closed. I still have to work out the quotienting of manifolds, but I know where to look now.
Mar
14
comment Image of Homomorphism of Lie groups
So it is really not clear to me how tu put topology and smooth structure on $Im(f)$ so that everything works out.
Mar
14
comment Image of Homomorphism of Lie groups
I am using definition which says that Lie subgroup is immersed submanifold (so not necesseraly with subspace topology).
Mar
13
revised Image of Homomorphism of Lie groups
added 4 characters in body
Mar
13
asked Image of Homomorphism of Lie groups
Feb
26
comment Eilenberg Moore category
On morphisms just Ff=Tf, no need for ordered pair, because morphism of T-algebras is just morphism in $C$ with some aditional properties.
Feb
13
comment Does an adjoint pair fix a unit/counit pair?
Yeah, but I think it is a fun exercise.
Feb
13
revised Does an adjoint pair fix a unit/counit pair?
edited body
Feb
13
revised Does an adjoint pair fix a unit/counit pair?
added 675 characters in body
Feb
13
answered Does an adjoint pair fix a unit/counit pair?
Jan
28
comment Help with a proof of Zorn's lemma
Dear Brian M. Scott, thank very much you for your help!
Jan
28
accepted Help with a proof of Zorn's lemma
Jan
28
revised Help with a proof of Zorn's lemma
added 124 characters in body
Jan
28
comment Help with a proof of Zorn's lemma
The argument seems circular. How do I know $X=\{u \in L \colon u<z\} \supseteq \{u∈L_1 \colon u<z\}$? And moreover, how do I see that $z=\inf_{L_1}(L_1\setminus L)$ exists? (I can't use that $L$ is initial segment in $L_1$ because I want to prove that.)
Jan
28
comment Help with a proof of Zorn's lemma
That would solve my problems if I could prove it! So if $x \in L$, $y \in L_1$ and $y<x$, i must see that $y \in L$. If $L_1 \subseteq L$ I am finished, so assume $L \subsetneq L_1$. How can I derive contradiction? I guess using the definition of $\cal L_0$ in some way, but i don't seem to manage it.
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