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7
votes
Every subset of $\mathbb{R}$ with finite measure is the disjoint union of a finite number of measurable sets
measure-theory
asked Jan 25 '11 at 1:07
math.stackexchange.com
7
votes
Explicit well-ordering of $\mathbb{N}^{\mathbb{N}}$
set-theory
asked Feb 27 '11 at 0:54
math.stackexchange.com
7
votes
For every $n < \omega$, $\aleph_n^{\aleph_0} = \max(\aleph_n,\aleph_0^{\aleph_0})$
set-theory
cardinals
asked Nov 16 '11 at 21:53
math.stackexchange.com
5
votes
Unit Ball of $\mathcal{l}_2$
functional-analysis
hilbert-spaces
asked Nov 5 '12 at 0:59
math.stackexchange.com
Top Answers
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