# Max Muller

Leiden, Netherlands

mathoverflow.net/users/5970/max-muller

Age: 23

I study mathematics at the University of Leiden. My interests include Analytic Number theory, Divergent Series, the Feynman Path Integral and mathematical games. I am also interested in how new media could be integrated to improve mathematics education, mathematical exposition and biographies of mathematicians.

My e-mail adres is maxmuller100 [at] hotmail [dot] com.

 Apr 21 awarded Popular Question Jan 19 awarded Notable Question Nov 25 awarded Nice Question Aug 11 awarded Yearling Aug 11 awarded Yearling Jul 3 awarded Nice Answer Jun 16 awarded Nice Question Jan 18 comment How to determine the order of the poles of this particular function?@JackD'Aurizio Can you please show me how this relates to the order of the poles? What result links the derivative of the function in the denominator to the poles? Jan 18 asked How to determine the order of the poles of this particular function? Jan 2 accepted How to compute $\lim_{s \to 1} (s-1) \frac{\zeta'(s)}{\zeta(s)}$ ? Dec 30 asked How to compute $\lim_{s \to 1} (s-1) \frac{\zeta'(s)}{\zeta(s)}$ ? Nov 28 asked How to prove that $\omega (n) = O\Big{(} \frac{\log(n)}{\log(\log(n))}\Big{)}$ as $n \to \infty$? Nov 26 comment How to answer the following question regarding a certain number of primes in a certain interval?@MarkBennet Nope, I haven't. Do you suspect that's a promising method? Nov 26 asked How to answer the following question regarding a certain number of primes in a certain interval? Nov 11 accepted How to prove that $\lim_{u \downarrow 1} (u-1) \zeta(u) =1$? Nov 11 comment How to prove that $\lim_{u \downarrow 1} (u-1) \zeta(u) =1$?I edited the question! Thanks. Nov 11 revised How to prove that $\lim_{u \downarrow 1} (u-1) \zeta(u) =1$?deleted 5 characters in body Nov 11 asked How to prove that $\lim_{u \downarrow 1} (u-1) \zeta(u) =1$? Oct 18 asked Is there an introductory book on Genetic Sequencing Theory for mathematicians? Oct 16 accepted Show that $\, 0 \leq \left \lfloor{\frac{2a}{b}}\right \rfloor - 2 \left \lfloor{\frac{a}{b}}\right \rfloor \leq 1$