|
8h
|
|
comment |
Solve this equation symbolically @user71346 For does not accumulate output, and is also inefficient here. (Read this.) Use Table instead: Table[vals, {a, -1, 1, 0.02}]
|
|
10h
|
|
revised |
Why don't these styling rules work when viewed in TableForm? deleted 9 characters in body |
|
10h
|
|
answered | Why don't these styling rules work when viewed in TableForm? |
|
15h
|
|
comment |
How to combine SparseArray and If @Mencia I have updated my answer. |
|
15h
|
|
revised |
How to combine SparseArray and If added 729 characters in body |
|
16h
|
|
comment |
Beginner's question: Gap between FrameLabel and BarChart @Stefan For what it's worth the output (from this) looks a bit different on version 7, and the longer code was required to match your output. Also, I believe you should be able to use the slightly shorter PlotRangePadding -> 0 to produce the same output as given by PlotRangePadding -> {0, 0}.
|
|
16h
|
|
comment |
vectorized operations is not efficient? @explorer I believe you are asking: is UnitStep[1 - r] equivalent to 1 - UnitStep[r - 1]? Not precisely, because of the case of 1: {UnitStep[1 - r], 1 - UnitStep[r - 1]} /. r -> 1. It is unlikely to make a difference in your application however, IMHO, but to be rigorous I used the longer form.
|
|
17h
|
|
reviewed | Leave Open Generating a list of all factorizations |
|
1d
|
|
awarded | Popular Question |
|
1d
|
|
answered | Beginner's question: Gap between FrameLabel and BarChart |
|
1d
|
|
comment |
Beginner's question: Gap between FrameLabel and BarChart Welcome, Stefan. I embedded the images for you. The image/link limitation is an anti-spam measure that will be lifted once you start using the site more. |
|
1d
|
|
revised |
Beginner's question: Gap between FrameLabel and BarChart added 85 characters in body |
|
1d
|
|
revised |
Variable scoping problem when mapping over delayed replacement added 1 characters in body |
|
1d
|
|
comment |
How could I find the correct values for every array that would lead me to unique summation number for every unique chain? @m.rizeg somehow missed your comment that you aren't using Mathematica. In light of this, regarding our earlier discussion, I'll let the StackOverflow folks try answering this to your satisfaction (after all there are a lot more of them). You're still welcome in the Mathematica.SE chat room of course. |
|
1d
|
|
answered | Applying a function with the HoldAll attribute inside NestList |
|
1d
|
|
revised |
vectorized operations is not efficient? added 443 characters in body |
|
1d
|
|
comment |
Solve this equation symbolically @user71346 you could substitute an arbitrary real value for a and convert to numeric values with N. This will not prove that certain solutions are always real (I think), but it can help you eliminate the ones that return complex values. Try: sols /. a -> 1 // N
|
|
1d
|
|
answered | vectorized operations is not efficient? |
|
1d
|
|
revised |
vectorized operations is not efficient? deleted 5 characters in body |
|
1d
|
|
comment |
Solve this equation symbolically @user71346 I see I missed a major aspect of your updated question: the Root objects! Please see this fine answer.
|
