1d
comment Combining two conditional probability distributions; what is the variance?
If they are truly independent, their covariance is 0. <br> Does that then mean that in this example, $\sigma_11$ would be the variance of the first distribution, $\sigma_12$ would be 0, and $\sigma_22$ would be the variance of the second distribution - effectively making the matrix [$a_1^2$+1/(1-$a_1a_2)^2$, $a_2^2+1/(1-a_1a_2)^2$]?
1d
comment Combining two conditional probability distributions; what is the variance?
I think that is the case; to look at them simultaneously as if they were independent. But I was under the impression that the variance of ($Y_1,Y_2 | Z_1, Z_2$) would be a covariance matrix. Is this correct? Or would the variance of the distribution simply be a vector, containing the two variances from each conditional distribution?
1d
asked Combining two conditional probability distributions; what is the variance?
2d
asked How to calculate distribution of (X1, X2) conditional on (C1, C2)?
Aug
27
comment How to calculate distribution of (X1, X2) conditional on (C1, C2) in statistical model?
Sorry; I should've clarified. $E_{1,2}$ are the only random variables. But in that case, how do you determine the mean and variance of the distribution ($X_{1}$,$X_{2}$|$C_{1}$,$C_{2}$)? Is it possible to represent it in a format with one mean and one variance?
Aug
27
comment How to calculate distribution of (X1, X2) conditional on (C1, C2) in statistical model?
While I am able to solve $X_{1}$,$X_{2}$ in terms of the other variables, I am not sure how to approach estimating the distribution (conditional on $C_{1}$,$C_{2}$) even with an expression for $X_{1}$,$X_{2}$
Aug
27
asked How to calculate distribution of (X1, X2) conditional on (C1, C2) in statistical model?
May
1
comment Min/Max Expectation problem (very difficult)
This suggests that there is a probability of 0 that a request for 3 or more salmon will be made. As such the only requests that can be made are for 0, 1, or 2 salmon. There is a 25% chance that the request will be 0, a 50% chance the request will be 1 and a 25% chance the request will be 2. This means that there is a 75% chance that the request will be for at least one salmon. The expected value of stocking one salmon is $1.50 (0.75x2). This is higher than the expected value of stocking 2 salmon (0.25x4), and so the profit maximizing amount should be x=1.
May
1
answered Min/Max Expectation problem (very difficult)
May
1
awarded Student
May
1
asked Example questions for bias/consistent estimators.