|
21h
|
|
reviewed | Close A intersects B complements |
|
1d
|
|
reviewed | Leave Open Is there any way to save this "proof" that $\aleph_0=\aleph$? |
|
1d
|
|
answered | Fibers and they being discrete space |
|
1d
|
|
comment |
Fibers and they being discrete space What reference says the fiber of a fiber bundle is discrete? |
|
1d
|
|
reviewed | Leave Open Find an equation for the tangent to the curve at the given point. |
|
1d
|
|
reviewed | Close if $A$ is Abelian group , $B$ is subgroup of $A$ , Is $B \times A/B \cong A$? |
|
2d
|
|
revised |
Ergodic action of a group edited tags |
|
2d
|
|
reviewed | Close Tension in parallel springs |
|
Jun
15 |
|
reviewed | Leave Open Infinite sets don't exist!? |
|
Jun
15 |
|
reviewed | Leave Open Statistics and Probability |
|
Jun
15 |
|
reviewed | Leave Open What is a null set? |
|
Jun
15 |
|
reviewed | Close statistics and probability |
|
Jun
15 |
|
reviewed | Close Explanation of why $\frac{d}{dx} e^x=e^x$ |
|
Jun
15 |
|
reviewed | Leave Open Statistics and Probability |
|
Jun
14 |
|
reviewed | Reject suggested edit on Math Course Advice |
|
Jun
14 |
|
reviewed | Reopen Maximum Likelihood Estimator |
|
Jun
14 |
|
comment |
Does $\mathrm{Mat}_{m \times n}$ have boundary? Yes, that works. |
|
Jun
14 |
|
comment |
Does $\mathrm{Mat}_{m \times n}$ have boundary? The second paragraph of my answer explains this. You should read the conditions in GP68 as "only $X$ is allowed to have boundary, all other manifolds in question must be boundaryless." So $X$ does not have to have a nonempty boundary. This is really a condition imposed on $Y$, $Z$, and $S$, since we are saying they cannot have boundary. $X$ can have any boundary possible, including the empty boundary! |
|
Jun
14 |
|
reviewed | Close How to find the evvects of Elementary Row Opperations on a determinant? |
|
Jun
14 |
|
comment |
Concerning the tangent space of an exotic $\mathbb R^4$ @levitopher Isomorphism classes of rank $k$ vector bundles over a paracompact, Hausdorff topological space $X$ are classified by homotopy classes of maps $[X, BO(k)]$. When $X$ is paracompact, Hausdorff, and contractible this implies that the only vector bundle over $X$ is the trivial bundle. Manifolds are paracompact and Hausdorff topological spaces, so we can apply the argument (even in the noncompact case). |
