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Dec
19
awarded Popular Question
Dec
15
awarded Caucus
Dec
15
revised Condition of the mean value theorem
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Dec
15
comment Condition of the mean value theorem
However if you know only the less general version you could say, that $f$ has the MVT on every closed sub-interval of $]-1,1[$. What about the theorems (see question above).
Dec
15
awarded Critic
Dec
15
asked Condition of the mean value theorem
Dec
3
revised Does every differentiable function has an infliction point between a local maximum and minimum?
added 156 characters in body
Dec
2
comment Does every differentiable function has an infliction point between a local maximum and minimum?
Furthermore $x$ beeing a local extremum doesn't imply that $f''(x) \neq 0$ (only that $f'(x)=0$).
Dec
2
awarded Commentator
Dec
2
comment Does every differentiable function has an infliction point between a local maximum and minimum?
Thanks. But in the non strict case, is the theorem true or is there another counterexample?
Dec
2
comment Does every differentiable function has an infliction point between a local maximum and minimum?
This is not the definition of inflection point. It is just a neccesary condition if $f$ is twice differentiable. It would be a sufficient condition for example if $f$ is three times differentiable and additionally $f'''(x) \neq 0$.
Dec
2
revised Does every differentiable function has an infliction point between a local maximum and minimum?
added 34 characters in body
Dec
2
revised Does every differentiable function has an infliction point between a local maximum and minimum?
added 34 characters in body
Dec
2
asked Does every differentiable function has an infliction point between a local maximum and minimum?
Nov
26
awarded Promoter
Nov
22
awarded Popular Question
Nov
8
awarded Notable Question
Oct
19
comment Asymptote of solution of a differential equation without solving it
I don't really understand why it is sufficient to show that $u'(x) > 0$ for all $x$ and why this it the case. If $u'(x_0) = 0$ for some $x_0$, why is this automatically the case for all $x$?
Oct
18
revised Intiutive argument that $\exp' = \exp$
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Oct
15
revised Intiutive argument that $\exp' = \exp$
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